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define the structure's field order with metadata #954
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If you walk the inheritance structure here, you'll miss classes, that extend Structure, but don't use the annotation. So what I would do at this point:
super.getFieldOrder()
callThis way you can mix the definitions. As the order is caches, this should not have a big impact on performance.
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not fixed
I thought about it but I don't agree, because if a class overrides this method no sub class can call the default implementation i.e. getting with annotation
plus calling
getClass()
insuper.getFieldOrder()
will result in the same class as it would if you write it here and therefore will result in aStackOverflowException
.Could you show me an example perhaps?
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BTW I had another idea to check in
this.fieldOrder
if we already got fields for the super class and use them instead of iterating the inheritance structure. what do you think, does it worth the effort?There was a problem hiding this comment.
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You are right - subclasses can still call
super#getFieldOrder
and so build a complete list if a super class uses the@FieldOrder
annotation. It will fail if a child class is using the annotation and the super class is not. In this case the member check at runtime will blow. For the 5.0.0 release it would be ok to update all structures in the platform.There was a problem hiding this comment.
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Notice that if the the parent class's
getFieldOrder
method was overridden there is no way to call the original code ofStructure#getFieldOrder
therefor if the user wants to extend the parent class he must overridegetFieldOrder
and add the new fields manually.I can create an helper method to use when using an old library(without the usage of
@FieldOrder
) so the user could just overridegetFieldOrder
and returngetNonAnnotatedAndAnnotatedFieldOrder()
, but it seems to be error prone(in this configuration: classWithAnnotation extends classWithout extends classWith extends classWithout)Should I add it anyway?